faster `slicef-at`

pull/2/head
Matthew Butterick 10 years ago
parent ed2d1de315
commit 0a6db2e350

@ -11,14 +11,19 @@
(define+provide/contract (slicef-at xs pred [force? #f])
((list? procedure?) (boolean?) . ->* . list-of-lists?)
(cond
[(null? xs) null]
[force? (slicef-at (dropf xs (compose1 not pred)) pred)]
[else
(define-values (car-match others) (splitf-at xs pred))
(define-values (head tail) (splitf-at others (compose1 not pred)))
(cons (append (or car-match null) head) (slicef-at tail pred force?))]))
(define-values (last-list list-of-lists)
(for/fold ([current-list empty][list-of-lists empty])([x (in-list xs)])
(if (pred x)
(values (cons x null) (if (not (empty? current-list))
(cons (reverse current-list) list-of-lists)
list-of-lists))
(values (cons x current-list) list-of-lists))))
(let ([list-of-lists (reverse (if (empty? last-list)
list-of-lists
(cons (reverse last-list) list-of-lists)))])
(if (and force? (not (empty? list-of-lists)) (not (pred (caar list-of-lists))))
(cdr list-of-lists)
list-of-lists)))
(define+provide/contract (slice-at xs len [force? #f])
((list? (and/c integer? positive?)) (boolean?) . ->* . list-of-lists?)
@ -31,13 +36,16 @@
list-of-lists
(cons (reverse last-list) list-of-lists))))
(define+provide/contract (filter-split xs split-test)
;; this function could possibly be implemented as a post-processing step on slicef-at:
;; every list after the first list starts with an element matching pred.
;; so drop the first element from all lists except the first.
;; (cons (car xs) (map cdr (cdr xs)))
(define+provide/contract (filter-split xs pred)
(list? predicate/c . -> . list-of-lists?)
(define-values (last-list list-of-lists)
(for/fold ([current-list empty][list-of-lists empty])
([x (in-list xs)])
(if (split-test x)
(if (pred x)
(values empty (if (not (empty? current-list))
(cons (reverse current-list) list-of-lists)
list-of-lists))

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