take account of hide property in rule flattening (fixes #8)

pull/10/head
Matthew Butterick 8 years ago
parent cf505f2995
commit c85b0e5cc9

@ -44,17 +44,17 @@
;; derived rules.
(define (lift-nonprimitive-pattern a-pat)
(cond
[(primitive-pattern? a-pat)
(values '() (linearize-primitive-pattern a-pat))]
[(hash-has-key? ht (pattern->hash-key a-pat))
(values '() (list (hash-ref ht (pattern->hash-key a-pat))))]
[else
(define head (syntax-case a-pat () [(head rest ...) #'head]))
(define new-name (datum->syntax #f (fresh-name) a-pat))
(define new-inferred-id (datum->syntax #f `(inferred-id ,new-name ,head) a-pat))
(hash-set! ht (pattern->hash-key a-pat) new-inferred-id)
(values (recur #`(rule #,new-name #,a-pat) head)
(list new-inferred-id))]))
[(primitive-pattern? a-pat)
(values '() (linearize-primitive-pattern a-pat))]
[(hash-has-key? ht (pattern->hash-key a-pat))
(values '() (list (hash-ref ht (pattern->hash-key a-pat))))]
[else
(define head (syntax-case a-pat () [(head rest ...) #'head]))
(define new-name (datum->syntax #f (fresh-name) a-pat))
(define new-inferred-id (datum->syntax #f `(inferred-id ,new-name ,head) a-pat))
(hash-set! ht (pattern->hash-key a-pat) new-inferred-id)
(values (recur #`(rule #,new-name #,a-pat) head)
(list new-inferred-id))]))
(define (lift-nonprimitive-patterns pats)
(define-values (rules patterns)
@ -105,12 +105,12 @@
(with-syntax ([(sub-pat ...) new-sub-pats])
(cons (cond [(= (syntax-e #'min) 0)
#`(head origin name
[(inferred-id name repeat) sub-pat ...]
[])]
[(inferred-id name repeat) sub-pat ...]
[])]
[(= (syntax-e #'min) 1)
#`(head origin name
[(inferred-id name repeat) sub-pat ...]
[sub-pat ...])])
[(inferred-id name repeat) sub-pat ...]
[sub-pat ...])])
inferred-rules)))]
[(maybe sub-pat)
@ -133,8 +133,22 @@
;; Given a pattern, return a key appropriate for a hash.
;;
;; In the `ragg` days this used `syntax->datum` only.
;; The problem is that with cuts & splices in the mix, it creates ambiguity:
;; e.g., the pattern (/"," foo)* and ("," foo)* differ only in the 'hide syntax property
;; so `syntax->datum` does not capture their differences.
;; That means they produced the same hash key,
;; which meant they produced the same inferred pattern. Which is wrong.
;; So we adjust the key to take account of the 'hide property
;; by "lifting" it into the datum with cons.
;; Then the pattern-inference process treats them separately.
(define (pattern->hash-key a-pat)
(syntax->datum a-pat))
(let loop ([x a-pat])
(let ([maybe-stx-list (syntax->list x)])
(if maybe-stx-list
(cons (syntax-property x 'hide) (map loop maybe-stx-list))
(syntax->datum x)))))
;; Returns true if the pattern looks primitive

@ -0,0 +1,4 @@
#lang brag
top : expr (/"," expr)*
expr : "x" | list
list : "(" expr ("," expr)* ")"

@ -0,0 +1,9 @@
#lang racket/base
(require brag/examples/cutter
brag/support
rackunit)
;; related to rule-flattening problem
(check-equal?
(parse-to-datum (list "(" "x" "," "x" ")"))
'(top (expr (list "(" (expr "x") "," (expr "x") ")"))))
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