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@ -198,3 +198,31 @@
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(define-syntax-rule (br:define+provide arg ...)
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(define+provide arg ...))
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(br:define #'(define-inverting (syntax (_id . _patargs)) _syntaxexpr)
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#'(define-syntax (_id stx)
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(let ()
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(define (expand-macro mac)
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(syntax-disarm (local-expand mac 'expression #f) #f))
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(syntax-case stx ()
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[(_ . rest)
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(with-syntax ([_patargs (map expand-macro (syntax->list #'rest))])
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_syntaxexpr)]))))
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(module+ test
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;; an inverting macro expands its arguments.
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;; so `foo` does not get `(falsy a) (falsy b) (falsy c)` as arguments,
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;; but rather the result of their expansion, namely `((#f a) (#f b) (#f c))`
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;; and `tree` does not get `(foo (#f a) (#f b) (#f c))` as its first argument,
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;; but rather the result of its expansion, namely (a b c).
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(define-inverting #'(tree (_id ...) _vals)
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#'(let ()
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(define-values (_id ...) _vals)
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(list _id ...)))
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(define-inverting #'(foo (#f _id) ...) #'(_id ...))
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(define-syntax-rule (falsy id) (#f id))
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(check-equal? (tree (foo (falsy a) (falsy b) (falsy c)) (values 1 2 3)) '(1 2 3)))
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