#lang scribble/lp2
@ ( require scribble/manual aoc-racket/helper )
@aoc-title [ 20 ]
@defmodule [ aoc-racket/day20 ]
@link [ " http://adventofcode.com/day/20 " ] { The puzzle } . Our @link-rp [ " day20-input.txt " ] { input } is a target number of presents , in this case @racket [ 36000000 ] .
@chunk [ <day20>
<day20-setup>
<day20-q1>
<day20-q2>
<day20-test> ]
@section { What ' s the first house that gets the target number of presents? }
The puzzle imagines infinite elves delivering presents to an infinite sequence of houses. ( Already @link [ " http://practicaltypography.com/the-infinite-pixel-screen.html " ] { I like } this puzzle. ) The first elf delivers a present to every house equal to 10 times his number ( = 10 ) ; the second elf, 20 gifts to every second house; the @italic{n}th elf, 10@italic{n} gifts to every @italic{n}th house.
Math jocks will notice that the elf behavior roughly describes a @link [ " https://en.wikipedia.org/wiki/Sieve_of_Eratosthenes " ] { Sieve of Eratosthenes } . Each house is visited by elf @italic { n } only if @italic { n } is a divisor of the house number. ( Houses that are primes are therefore only visited by the first elf. ) Might there be a Racket function that finds the divisors of a number? Why , yes — it ' s called @racket [ divisors ] . We can use it to find the numbers of the elves that visit a house , and loop through house numbers till we reach the target. ( The 10-gift multiplier is arbitrary. )
@chunk [ <day20-setup>
( require racket rackunit ( only-in math divisors ) )
( provide ( all-defined-out ) )
]
@chunk [ <day20-q1>
( define ( q1 input-str )
( define target-gifts ( read ( open-input-string input-str ) ) )
( define gifts-per-elf 10 )
( for/first ( [ house-number ( in-naturals ) ]
#:when ( let* ( [ elves ( divisors house-number ) ]
[ elf-gifts
( apply + ( map ( curry * gifts-per-elf ) elves ) ) ] )
( >= elf-gifts target-gifts ) ) )
house-number ) ) ]
@section { What ' s the first house that gets the target number of presents , if each elf delivers 11 gifts to 50 houses? }
Going with the math-jock vibe , what this condition means is that the highest-numbered house the @italic { n } th elf will visit is 50@italic { n } . So the answer for this question is like the first , but we ' ll @racket [ filter ] the list of elves using this condition.
@chunk [ <day20-q2>
( define ( q2 input-str )
( define target-gifts ( read ( open-input-string input-str ) ) )
( define gifts-per-elf 11 )
( for/first ( [ house-number ( in-naturals ) ]
#:when ( let* ( [ elves ( divisors house-number ) ]
[ elves ( filter
( λ ( e ) ( <= house-number ( * 50 e ) ) ) elves ) ]
[ elf-gifts
( apply + ( map ( curry * gifts-per-elf ) elves ) ) ] )
( >= elf-gifts target-gifts ) ) )
house-number ) )
]
@section { Testing Day 20 }
@chunk [ <day20-test>
( module+ test
( define input-str ( file->string " day20-input.txt " ) )
( check-equal? ( q1 input-str ) 831600 )
( check-equal? ( q2 input-str ) 884520 ) ) ]